b^2x^2-5bx+4=0

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Solution for b^2x^2-5bx+4=0 equation:


Simplifying
b2x2 + -5bx + 4 = 0

Reorder the terms:
4 + -5bx + b2x2 = 0

Solving
4 + -5bx + b2x2 = 0

Solving for variable 'b'.

Factor a trinomial.
(1 + -1bx)(4 + -1bx) = 0

Subproblem 1

Set the factor '(1 + -1bx)' equal to zero and attempt to solve: Simplifying 1 + -1bx = 0 Solving 1 + -1bx = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1bx = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1bx = 0 + -1 -1bx = 0 + -1 Combine like terms: 0 + -1 = -1 -1bx = -1 Divide each side by '-1x'. b = x-1 Simplifying b = x-1

Subproblem 2

Set the factor '(4 + -1bx)' equal to zero and attempt to solve: Simplifying 4 + -1bx = 0 Solving 4 + -1bx = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1bx = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1bx = 0 + -4 -1bx = 0 + -4 Combine like terms: 0 + -4 = -4 -1bx = -4 Divide each side by '-1x'. b = 4x-1 Simplifying b = 4x-1

Solution

b = {x-1, 4x-1}

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